f(-2)=10(2^-2)

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Solution for f(-2)=10(2^-2) equation: 



f(-2)=10(2^-2)

We move all terms to the left:

f(-2)-(10(2^-2))=0

We add all the numbers together, and all the variables

f(-2)-2.5=0

We multiply parentheses

-2f-2.5=0

We move all terms containing f to the left, all other terms to the right

-2f=2.5

f=2.5/-2

f=-1+0.5/2

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